INPUT: List1: //depot/asic/tools/perl/scripts/examples/modem.c#7

//depot/asic/tools/perl/files/examples/file.txt#2

//depot/asic/tools/perl/proc/examples/apps.c#14

List2: //depot/asic/tools/perl/scripts/examples/modem.c#6

//depot/asic/tools/perl/files/examples/file.txt#2

//depot/asic/tools/perl/proc/examples/apps.c#12

OUTPUT: Picking File2 overwrites

//depot/asic/tools/perl/scripts/examples/modem.c#7-> 6

//depot/asic/tools/perl/proc/examples/apps.c#14->12

1.What's wrong with the below code.I am getting the below error.Basically I want to print all the lower version filepaths in list2 compared to list1

syntax error at orphan_overwrite.pl line 25, near "}{" syntax error at orphan_overwrite.pl line 35, near "}" Execution of orphan_overwrite.pl aborted due to compilation errors.

2.Is the if condition"if ($2 < pathname_versions{$1}{$2} )" valid?Does pathname_versions{$1}{$2} give the version value in List1 ?How do I access the value for the matched path in list1 and compare? 

#!/usr/bin/perl

use strict;
use warnings;
use Data::Dumper;

@ARGV == 2 and -f $ARGV[0] or die "Usage: $0 list1 list2\n";
my ( $list1, $list2 ) = @ARGV;

my %pathname_versions;

open( IN, $list1 ) or die "$list1: $!";
while (<IN>) {
    next unless ( m:(.+?)#(\d+)$: );
    $pathname_versions{$1}{$2} = undef;

}
    print  Dumper( \%pathname_versions );
open( IN, $list2 ) or die "$list2: $!";
while (<IN>) {
    next unless ( m:(.+?)#(\d+)$: );
    #print "\nLIST 2:$1 $2";
    if ( exists( $pathname_versions{$1} ))
    {
        if ($2 < pathname_versions{$1}{$2} ) {#if the version in list2
+ is less than version for the same path in list1
            print "$1 pathname_versions{$1}{2}->$2";
        }

        if ( exists( $pathname_versions{$1}{$2} )) {
            # we have a match on version# as well, so...
        }
        else {
            # version number wasn't seen in list1, so...
        }
    }
}

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In reply to If condition failing.. by perl_mystery

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