I'm returning it in a function call...

In case the string is huge and you want to avoid some temporary memory allocation (which could push up the peak memory usage of the program), you could return a reference to the scalar:

#!/usr/bin/perl sub mem { print "$_[0]:\n"; system "/bin/ps", "-osize,vsize", $$; } sub foo { mem(0); my $data; $data .= "xxxxxxxxxx" for 1..1_000_000; mem(1); return \$data; # return reference } my $r = foo(); # then get at the data using $$r mem(2); __END__ $ ./880173.pl 0: SZ VSZ 612 19804 1: SZ VSZ 10468 29660 2: SZ VSZ 10468 29660

Using the same snippet, but with return $data, you'd get:

0: SZ VSZ 612 19804 1: SZ VSZ 10468 29660 2: SZ VSZ 20236 39428

As you can see, the process size has grown additionally by about the size of $data.

Whether this really saves anything overall depends on what else the program is doing to actually print the string, etc.


In reply to Re: Most efficient way to print a file? by Anonyrnous Monk
in thread Most efficient way to print a file? by Anonymous Monk

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