Is it possible to do $r = eval("$a $op $b")

In principle yes, if you map the operators 'le', 'ge' etc. to the corresponding Perl equivalents — e.g. using a hash. 

my %perlop = (
   le => '<=',
   ge => '>=',
   #...
);

my $r = eval "$a $perlop{$op} $b";

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(But as always with string eval, be careful what you interpolate when the data ($a, $b here) doesn't come from trusted sources...)

In reply to Re: eval question by Anonyrnous Monk
in thread eval question by rhymejerky

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