You can do this with the x operator as well:

perl -e '$x="ab"; $n= 20; @f= ($x) x $n; print join "|",@f;'
#prints
ab|ab|ab|ab|ab|ab|ab|ab|ab|ab|ab|ab|ab|ab|ab|ab|ab|ab|ab|ab

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In reply to Re: generating a list of identical elements by jethro
in thread generating a list of identical elements by rovf

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