This is because your string has taken the single escape char and escaped it for you If you run perl in debug mode and look at the following it will show
what I mean: 
$ perl -de0

Loading DB routines from perl5db.pl version 1.0402
Emacs support available.

Enter h or `h h' for help.

main::(-e:1):   0
  DB<1> my $string = '\\this is a test on \ escapes . ';

  DB<2> print $string
\this is a test on \ escapes . 
  DB<3> x $string
0  '\\this is a test on \\ escapes . '
  DB<4> $string =~ s/\\/\\\\/g;

  DB<5> print $string
\\this is a test on \\ escapes .

[download]

As you can see the evaluation of $string at step 3 shows it to now contain two backslashes where only one was entered.
This is because it has evaluated correctly a single backslash escape but doesn't evaluate \\ correctly. I assume that it assumes you are escaping and it need do nothing.
I think you're going to have to write a neat little subroutine accounting for all the above problems. A few smart substitution regex's combined with quotemeta should eventually cover all the bases....

In reply to Re: Re: Re: Re: Re: Backslash Interpolation by Graham
in thread Backslash Interpolation by Anonymous Monk

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