Your example creates a new anonymous hash that falls out of scope with each iteration of the loop. So in the simplest terms, it's not the same anonymous hash each time. The fact that a newly created anonymous hash has or doesn't have the same address as a previous one that has fallen out of scope is practically coincidental. More importantly, it shouldn't matter what is happening behind the curtain.


Dave

In reply to Re: Address of anonymous hash by davido
in thread Address of anonymous hash by aixtal

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