I was using ! operator today, and I notice a case where I expected a different output.

When I do !0, it results 1. But, when I do !1, it is neither returning 0 nor undef.

use 5.10.0;
use strict;
use warnings;

my $r = !1;

if (defined $r)  {
    say "Defined";
}
else  {
    say "Not defined";
}

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I don't understand, why it works this way. Help me to know what's happening in perl when I do this operation.

In reply to how ! operator works by nagalenoj

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