I was browsing here and found this Rot13 Challenge.

Rot13 Encryption is performed by shifting the letters 13 characters to the right. A becomes N, B becomes O. The cool thing about this is an encrypted string can be decrypted by using the same algorithm. IOW, the A becomes N, N becomes A.

my first thought was to convert the characters to their equivalent ascii number, shift it, then return the ascii character.

#!/usr/bin/perl

use strict;
use warnings;

use 5.010001;

my $input;
say "Please Enter String a string to be encrypted or decrypted";
$input = <>;
chomp $input;
my @ascii_char;
my $char;
while($input =~ m/(.)/g) {
    push @ascii_char, ord $1;
}

say @ascii_char;
open my $ENCRYPTED_STRING, '>', \my $encrypted_string;
foreach( @ascii_char ) {
    if ($_ >= 97 and $_ <= 122) {
        if ((122 - $_) <13 ){
            $_ = 97 + (13 - (123 - $_));
        }
        else {
            $_ += 13;
        }
    }
    elsif ($_ >= 65 and $_ <= 90) {
        if ((90 - $_) < 13 ){
            $_ = 65 + (13 - (91 - $_));
        }
        else {
            $_ += 13;
        }
    }

    print $ENCRYPTED_STRING chr;
}
close $ENCRYPTED_STRING;

say $encrypted_string;
[download]

Then I figured why not use the translate function...

#!/usr/bin/perl
use strict;
use warnings;
use 5.010001;

say 'Please Enter a String to be Encrypted or Decrypted';
my $input = <>;
chomp $input;

$input =~ tr/abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ/nopq
+rstuvwxyzabcdefghijklmNOPQRSTUVWXYZABCDEFGHIJKLM/;
say $input;
[download]

Considerably shorter.

So the challenge is this:

• Create the most succinct version
• Create the most obfuscated version.

Any takers?

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