Dear monks
I have a code as below: 
$MI_T=MI($hypo,$text,\%hash_es,\%hash_en);

sub MI {
    my ($string_es,$string_en,$hash_es,$hash_en)=@_;
    my @array_es= my @array_en = ();
    @array_es = split ' ', $hash_es{$string_es};
    @array_en = split ' ', $hash_en{$string_en};
    my $prob_es = ($#array_es+1)/6939873;
    my $prob_en = ($#array_en+1)/6939873;
    my $intersection= Intersection(\@array_es,\@array_en);
    my $prob_es_en= ($intersection)/6939873;
    $prob_es_en = ($prob_es_en + ($prob_es*$prob_en*0.1))/1.1;
    my $mi= $prob_es_en * log( $prob_es_en / ($prob_es * $prob_en) );
    return $mi;
}

sub Intersection {
    my( $refA, $refB ) = @_;

    my %counts;
    ++$counts{ $_ } for @$refA;
    ++$counts{ $_ } for @$refB;

    my $intersects = 0;
    $counts{ $_ } > 1 and ++$intersects for keys %counts;

    return $intersects;
}

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my hash is like this: (term is the key and the numbers are value of each term) 
term1      1 3 5 8 9 15 90
term2      23 56 789 23 1 54 89
term3      23 345 677 456 23
....
termn      54 6 768 5678 34 56 78

[download]
while the number of digits corresponding to each term can vary form 1 to n.
currently it takes a long time to calculate the $MI_T.
(sometimes 20-25 seconds). is there anyway to improve the code in order to calculate it faster? Thanks!

In reply to improving the speed by perl_lover_always

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