Thanks, it's my bug report. Here's my answer to Eric Brine
Let's present the re
'ab' =~ /((\w+)(?{print defined $2 ? "\$2=$2\n" : "\$2 not defined\n"})){2}/;
as
((\w+)(?{print...}))((\w+)(?{print...}))
Is \w{2} equivalent to \w\w, right? But we assume that the second copy of the re produces also the same $1 and $2 (not $3 and $4). Current position in the re marked with |.
1. First (\w+) captures all the text:
((\w+) | (?{print...}))((\w+)(?{print...}))
$2 receives the value 'ab', eval prints $2=ab.
2. Then we enter second copy of (\w+):
((\w+)(?{print...}))(( | \w+)(?{print...}))
$2 (and also $+, $^N, \2) receives the value undefined.
3. We see that \w not match. We do backtracking:
((\w+ | )(?{print...}))((\w+)(?{print...}))
We enter first copy of (\w+) from right to left, and $2 again receives the value undefined.
4. (\w+) captures the letter a:
((\w+) | (?{print...}))((\w+)(?{print...}))
$2 must receive the value a, but in current version of Perl $2 receives
undefined... Why? Probably, two values of undefined are stored in $2 as in a stack,
then last value is removed from the stack, and $2 again equal undefined?
Here eval must print $2=a.
5. Second copy of (\w+) captures the letter b:
((\w+)(?{print...}))((\w+) | (?{print...}))
Eval prints $2=b. Match successfull.
Do you see any mistake in this reasoning?
In reply to Re^2: A bug in Perl regex(?)
by Serge314
in thread A bug in Perl regex(?)
by Serge314
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