For example, the square root of -1 is supposed to be nan, since it cannot be precisely represented (within the domain of real numbers). However sqrt(-1) is not 0. It makes a lot more sense to treat i (which is a non-zero number in an extended domain) as true than false.
In reply to Re: NaNs are true
by PeterPeiGuo
in thread NaNs are true
by syphilis
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