An alternative to tranliterating to delete the \0 characters and then getting the length of what's left would be to complement the \0's, assigning to a scalar so as to count all non-nulls.

    my $count = $x =~ tr/\0//c;
    print "'$s' at offset $i matched" unless $count > 1;

[download]

It's six of one, a half-dozen of the other I suppose but I thought it might be worth a mention.

Cheers,

JohnGG

In reply to Re^2: generating hash patterns for searching with one mismatch by johngg
in thread generating hash patterns for searching with one mismatch by cedance

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