Why 10^257? A column is either in or not in the key. That would mean 2^100 possible solutions to try

Or are you refering only to the worst case of your algorithm? Seems using permutation/variation might lead to much overhead in the search. If the combination 2:4 were already tested for example, testing 4:2 is not necessary anymore

In reply to Re^2: Finding Keys from data by jethro
in thread Finding Keys from data by aartist

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