Why 10^257? A column is either in or not in the key. That would mean 2^100 possible solutions to try
For a unique key 'ab' is different to 'ba'.
So, it should be 100! + 99! + 98! + 97! ... so I rounded up 10^157.
To be honest, given the scale of the numbers, it makes little difference.
In reply to Re^3: Finding Keys from data
by BrowserUk
in thread Finding Keys from data
by aartist
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