where equal strength is determined mostly by the performance in the tournament
So, by pretending to the algorithm that every match is a draw before anything is played, the part of the logic I have quoted rates everyone equally. Then the second part of the Swiss algorithm matches players of equal results within the tournament to be highest rank against lowest rank - exactly what the OP wants. Unless I've misunderstood something.

Regards,

John Davies

In reply to Re^7: Algorithm problem: Order matches by difference between players by davies
in thread Algorithm problem: Order matches by difference between players by Dirk80

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