not quite:

The idea is to create one age and one name for each subdirectory. This grouping can be done by a hash. However you should use the "grouping-criteria" as hash-key. In your case it is $File::Find::dir. The rest of your logic can remain unchanged.

use strict; use warnings; use File::Find; @ARGV = ('.') unless @ARGV; my %age; my %name; sub oldest { return if ((defined $age{$File::Find::dir}) && ($age{$File::Find::di +r} < (stat($_))[9])); $age{$File::Find::dir} = (stat(_))[9]; $name{$File::Find::dir} = $File::Find::name; } find(\&oldest, @ARGV); foreach my $n (keys(%age)) { print $name{$n}." " . scalar(localtime($age{$n})) . "\n"; }

btw.: I'm unsure whether this is a homework-question or not ... if it is be sure that you totally understand the solution. I have seen many situations where a student couldn't explain some code supposedly written by himself. You don't want that happen to you! ;-)

Rata

In reply to Re^3: Listing old files by Ratazong
in thread Listing old files by Anonymous Monk

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