Here's an example I made, stripping it down. I didn't get the pseudo-hash error. However, I didn't get any sorting, either. This is almost exactly how I built the bigger thing, which did give me the pseudo-hash error. 

scorpion:/export/home/kinyonro-> cat abcd
#!/usr/local/bin/perl

use strict;

use efgh qw(do_thing);

my $foo = [ { blah => 'd' }, { blah => 'b' }, { blah => 'c' }, ];
my $sortfunc = sub { $a->{blah} cmp $b->{blah} };

my @bar = do_thing($foo, $sortfunc);

for my $hash (@bar) {
    print "$_ => $hash->{$_}\n" for keys %$hash;
    print "\n";
}
scorpion:/export/home/kinyonro-> cat efgh.pm
package efgh;

use Exporter;
our @ISA = qw(Exporter);

our @EXPORT_OK = qw(do_thing);

use Data::Dumper;

sub do_thing {
    my ($data, $func) = @_;

print Data::Dumper->Dump([$data]);
    my @bar = sort $func @$data;
print Data::Dumper->Dump([@bar]);

    return @bar;
}

1;
scorpion:/export/home/kinyonro-> abcd
$VAR1 = [
          {
            'blah' => 'd'
          },
          {
            'blah' => 'b'
          },
          {
            'blah' => 'c'
          }
        ];
$VAR1 = {
          'blah' => 'd'
        };
$VAR2 = {
          'blah' => 'b'
        };
$VAR3 = {
          'blah' => 'c'
        };
blah => d

blah => b

blah => c

[download]

I am very seriously sooooo confused about this. I've never ever worked with pseudo-hashes, and I don't think I ever will. All I know is that they are listrefs where the 0th element is a hashref and the other elements are listrefs. That isn't the case here. (The original data structure was a listref where the 0th element was a listref and the others were hashrefs, but I shifted off the listref, leaving me with a listref of hashrefs. *whimpers*)

In reply to Re: Pseudo-hash intrusion... by dragonchild
in thread Pseudo-hash intrusion... by dragonchild

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