You're very close: $string =~ s/\s*$//; As far as I know, tr can't tell position. One space is the same as any other. Hence the s///.

HTH

Update: Oops. Forgot the quantifier.

YA Update: Abigail is correct, + is better. That's what happens when you rush to fix an "oops"....

In reply to Re: Trailing spaces by VSarkiss
in thread Trailing spaces by TeKk9

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