It Computes the number π (3.14159...) using numerical integration.
To understand it, take into account that the area under the curve 1/(1+x**2) between 0 and 1 is π/4:
When executed in a single machine, it took 5.387676 seconds:#!/usr/bin/perl -w use strict; use GRID::Machine; use GRID::Machine::Group; use List::Util qw(sum); use Time::HiRes qw(time gettimeofday tv_interval); my @MACHINE_NAMES = split /\s+/, $ENV{MACHINES}; my @m = map { GRID::Machine->new(host => $_, wait => 5, survive => 1) +} @MACHINE_NAMES; my $c = GRID::Machine::Group->new(cluster => [ @m ]); $c->sub(suma_areas => q{ my ($id, $N, $np) = @_; my $sum = 0; for (my $i = $id; $i < $N; $i += $np) { my $x = ($i + 0.5) / $N; $sum += 4 / (1 + $x * $x); } $sum /= $N; }); my ($N, $np, $pi) = (1e7, 4, 0); my @args = map { [$_, $N, $np] } 0..$np-1; my $t0 = [gettimeofday]; $pi = sum($c->suma_areas(args => \@args)->Results); my $elapsed = tv_interval ($t0); print "Pi = $pi. N = $N Time = $elapsed\n";
When executed in a cluster with two nodes we get a speedup of 1.81 = 5.387676/2.977237:~/grid-machine$ export MACHINES=local ~/grid-machine$ perl examples/pi.pl Pi = 3.14159265358969. N = 10000000 Time = 5.387676
~/grid-machine$ export MACHINES='local imac' ~/grid-machine$ echo $MACHINES local imac ~/grid-machine$ perl examples/pi.pl Pi = 3.14159265358969. N = 10000000 Time = 2.977237
In reply to Re: Parallel SSH
by casiano
in thread Parallel SSH
by solaris7
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