Hello Perl Monks

This is my first question here, so please don't laugh.

Can anyone explain to me what's going on in this code?

#!/usr/bin/perl use strict; use warnings; sub foo ($) { my $x = shift; print "foo gets '$x'\n"; return ($x+2, 33); } my @a = foo(42); print "a=@a\n"; @a = sort(foo(42)); print "a=@a\n"; @a = (sort foo(42)); print "a=@a\n"; @a = sort foo(42); print "a=@a\n";
which produces the following output on my Linux system with Perl 5.10.1:
foo gets '42' a=44 33 foo gets '42' a=33 44 a=42 a=42

If I use old-style subs (i.e. &foo instead of foo), then it produces 'a=33 44' three times, which is what I'd expect.


In reply to New-style sub strangeness by ChrisDennis

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