Yes. It does all the steps:

  1. Upgrades the scalar to something that can hold the desired type if it can't already.
  2. Sets the value in the appropriate field of scalar.
  3. Sets the bit indicating the appropriate field of the scalar has data, clearing the bits for the other fields.
  4. Calls the scalar's set magic handler, if there is one.

In reply to Re: XSUB: pass scalar by reference and assign value by ikegami
in thread XSUB: pass scalar by reference and assign value by OlegG

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