Thanks! Fascinating solution except that I think it is not thread-safe.. 


TIMESTEP 0:

    Say, $h{$k} points to v1 
    Thread T0: Holding lock on v1
    Thread T1: Waiting on Lock on v1 

TIMESTEP 1:

    T0 changes $h{$k} = \$v2, releases lock on $v1

TIMESTAMP 2: (Thread T2 makes an entrance)

    Thread T2: Acquires Lock on v2, proceeds
    Thread T1: Acquires Lock on v1, proceeds
    <Race-around condition>

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In reply to Re^3: Avoid Locking Entire Hashes by jagan_1234
in thread Avoid Locking Entire Hashes by jagan_1234

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