But I did $var = *x

So did I. I said \*x also works.

it's not obvious that $val needs dereferencing.

I showed that it doesn't need dereferencing.

$gv = *x; @$gv => @x

Of course, one needs to use the sigil to access the components of the glob.

$gv = *x; $gv{ARRAY} # Obviously wrong. *$gv{ARRAY} # Ok

...and not this:

Do you really want print($count + 2) to use $count as a file handle?

print(STDOUT + 2) => print( { STDOUT } 2 )

Barewords will be handled as expected, but anything else followed by what could be an infix operator will be treated as an argument to that operator.

print(*STDOUT + 2) => print( { select() } *STDOUT+2 ) print(*$x + 2) => print( { select() } *$x+2 ) print($x + 2) => print( { select() } $x+2 )

In reply to Re^3: typeglob: $var = *x ??? by ikegami
in thread typeglob: $var = *x ??? by 7stud

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