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Can someone help me with this perl pattern match, I am a newbie and write very little perl. I have a $out placeholder which could hold the following values in its

HostName: LAP3220889 TaskName: infiniteloop Next Run Time: Never Status: Last Run Time: 21:45:18, 22/06/2011 Last Result: 0 or HostName: LAP3220889 TaskName: infiniteloop Next Run Time: 11:06:00, 23/06/2011 Status: Running Last Run Time: 10:10:04, 23/06/2011 Last Result: 0 <code/> <p> I need to match taskname which is picked up from an existing variable +value, then I need to match Status: and its value (either "Running" o +r ""), then I need to match Last Result with its value. So out the d +ata I need to match the following (for example) </p> <code> TaskName: infiniteloop Status: Running Last Result: 0

This is my current code

if($out =~ m/TaskName:\s+$task.*?Status:\s+(.*?)\sLast Run Time:\s+(.* +?)\sLast Result:\s+(\d)/s) { chomp($status = $1); $result = $3;

which matches but I have to add \sLast Run Time:\s+(.*?) so it picks up Status value correctly My pattern should be

if($out =~ m/TaskName:\s+$task.*?Status:\s+(.*?)\sLast Result:\s+(\d)/ +s) { chomp($status = $1); $result = $2;

Im struggling with the match on Status, in a data dump this picks up

$VAR1 = 'infiniteloop'; $VAR2 = 'Running Last Run Time: 21:28:57, 23/06/2011'; $VAR3 = '0';

As you can see the status pattern match slurps all the data until it matches the start of "Last Result:" string from the data in $out This is probably very simple, I need a pattern to terminate at the end of status (VAR2) line and jump forward to match Last Result. Can anyone help?


In reply to regex pattern match by MarcAllan

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