Your substitution will correctly leave the \n in \\n alone, but what about \\\n? The backslash preceeding \n is itself preceeded by a backslash, so the \n should be converted in that case. \\\\n, on the other hand, shouldn't get the \n converted.

What is needed is something to match pairs of backslashes before the \n, like this: s/((?<!\\)(?:\\\\)*)\\n/$1\n/g;

In reply to Re: Re: reverse quotemeta? by chipmunk
in thread reverse quotemeta? by sparky8342

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