Unless your ok with just using chop on the result — at which point it will only work if the input length is odd — it is impossible to recreate your original data since multiple inputs encode identically.
$ perl -e'print pack "H*", "abc";' | od -t x1 0000000 ab c0 0000002 $ perl -e'print pack "H*", "abc0";' | od -t x1 0000000 ab c0 0000002
If you don't care about preserving leading zeroes, you can use
my $bin = pack("H*", ( length($hex) % 2 ? '0' : '' ).$hex); ... ( my $hex = unpack('H*', $bin) ) =~ s/^0+(?!\z)//;
If you don't care about preserving leading zeroes, you can use
my $bin = pack("H*", "".reverse $hex); ... ( my $hex = reverse unpack('H*', $bin) ) =~ s/^0+(?!\z)//;
If you do care about preserving leading zeroes, you can use
my $bin = pack("NH*", length($hex), $hex) ... my ($length, $hex) = unpack('NH*', $bin); substr($hex, $length, length($hex), '');
In reply to Re: Reconstruct binary data saved with unpack("H*", $b)
by ikegami
in thread Reconstruct binary data saved with unpack("H*", $b)
by andreas1234567
| For: | Use: | ||
| & | & | ||
| < | < | ||
| > | > | ||
| [ | [ | ||
| ] | ] |