Hello Perlmonks,

i have a question for parsing the csv file. i had csv file and have each row like this:

'car reg, location, 'gps string: lats:xxxx,longs:xxxxx, Alts:xxxx', number of satellites fix';

how can i split this into an array, so it has 4 values ? i know how to do this with double quotation, but not sure with single. there must be someway to do it. i also tried the Text::ParseWords, but not sure how to use it with parsing csv file. anyone can help ?

i also attached my code here: 
#!/usr/bin/perl

use strict;
use warnings;

use Text::CSV;
my $parser = Text::CSV->new();

sub trim($);
my $scomma = "@";
my $nline = "\n";

open (TEMP, $file) or die("Error: cannot open $file\n");
open (OUTPUT,">$outfile") or die("Error: cannot open $outfile\n");

while (my $line = <TEMP>) {
    if ($parser->parse($line)) {
    my @fields = $parser->fields();
    print OUTPUT trim($fields[0]).$scomma.trim($fields[1]).($fields[2]
+).$scomma.trim($fields[3]).$scomma.trim($fields[17]).$scomma.trim($fi
+elds[18]).$nline;
    }
}

[download]
thanks !

In reply to How to parse a csv file by comma, but ignore comma inside the single quotation by hujunsimon

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