I found this to be an interesting exercise in Date::Pcalc (this is the Perl only version of Date::Calc).

This demo script uses File::Find to go through a given directory and prints out all files older than a given date limit, in business days, that is, without counting Saturdays or Sundays (but still without legal holidays - note that can be done, too, with the Date::Pcalc holiday calendar feature).

Run like this for demo: perl older_than_days.pl -v 10

#!/usr/bin/perl -w
use strict;

use File::Find;
use Date::Pcalc qw(:all);
use Getopt::Std;

my %opts = ();
getopts('d:l:v' , \%opts);
die "\nUsage: $0 [-d startdirectory] [-v verbose] age_limit_in_days \n
+\n" 
    unless @ARGV;

my $start_dir = $opts{d} || ".";
my $verbose   = $opts{v} || 0;
my $day_limit = $ARGV[0] || "10";

find(\&wanted, $start_dir);

sub wanted {
    my $filename = $_;
    my $age = (stat $filename)[8];
    print "Processing file          : " . $filename, "\n" 
    if $verbose;
    return unless is_older_than($age, $day_limit);
    # put your delete code here - to dangerous to actually do it in de
+mo script
    print "Would delete $filename, it's older than $day_limit business
+ days ...\n\n";
}

sub is_older_than {
    my ($age, $days) = @_;

    my ($sec,$min,$hour,$mday,$mon,$year,$wday,$yday,$isdst) = localti
+me($age);

    # months start at 1 in Date::Pcalc and at 0 in localtime
    $mon++;
    # year is base 1900 in localtime, base 0 in Date::Pcalc
    $year += 1900;

    if ($verbose) {
    print "Today is                 : " . 
        join ' ', Today(), "\n";
    print "File last accessed       : " . 
        join ' ', $year, $mon, $mday, "\n";
    print "File age in days         : " . 
        Delta_Days($year, $mon, $mday, Today()), "\n";
    print "File age in business days: " . 
        Delta_Business_Days($year, $mon, $mday, Today()), "\n";
    }

    return 1 if Delta_Business_Days($year, $mon, $mday, Today()) > $da
+ys;
    return 0;
}

# From the Date::Pcalc manual
#    15) How can I calculate the difference in days between dates, but
#        without counting Saturdays and Sundays?

          sub Delta_Business_Days
          {
              my(@date1) = (@_)[0,1,2];
              my(@date2) = (@_)[3,4,5];
              my($minus,$result,$dow1,$dow2,$diff,$temp);

              $minus  = 0;
              $result = Delta_Days(@date1,@date2);
              if ($result != 0)
              {
                  if ($result < 0)
                  {
                      $minus = 1;
                      $result = -$result;
                      $dow1 = Day_of_Week(@date2);
                      $dow2 = Day_of_Week(@date1);
                  }
                  else
                  {
                      $dow1 = Day_of_Week(@date1);
                      $dow2 = Day_of_Week(@date2);
                  }
                  $diff = $dow2 - $dow1;
                  $temp = $result;
                  if ($diff != 0)
                  {
                      if ($diff < 0)
                      {
                          $diff += 7;
                      }
                      $temp -= $diff;
                      $dow1 += $diff;
                      if ($dow1 > 6)
                      {
                          $result--;
                          if ($dow1 > 7)
                          {
                              $result--;
                          }
                      }
                  }
                  if ($temp != 0)
                  {
                      $temp /= 7;
                      $result -= ($temp << 1);
                  }
              }
              if ($minus) { return -$result; }
              else        { return  $result; }
          }

# NOTE THIS:
#        This solution is probably of little practical value,
#        however, because it doesn't take legal holidays into
#        account.
[download]

Christian Lemburg
Brainbench MVP for Perl
http://www.brainbench.com

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