Hello guys

Let there be a hash

%def = ( default_option_use_log => 1, default_option_read_conf => 1, default_option_run_debug => "false", default_output_path => "/tmp/vvv", default_name => "stat_", default_option_save_state => "true" );

We need to fill a new hash with keys based on filtered and changed keys of %def hash. Consider the following code:

foreach (map { /^default_option_(.*)/ ? $1 : () } keys %def) { $s{"option_$_"} = $def{"default_option_$_"}; } foreach (keys %s) { print "\%s: $_ => $s{$_}\n"; }

Is there a way to shorten the 'foreach' block or may be use different approach instead of 'foreach'. It would be great to eliminate double using 'default_option_' string, also '? : ()' condition looks not perfect. I need a nice-looking, laconic, as much Perl-ish as possible, solution.

Thanks


In reply to get solution as short as possible by Anonymous Monk

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