SUPER relates to the class in which the code using it is compiled. It doesn't involve the invocant.

  1. son->new looks in son and its ancestors for a new and calls father::new.
  2. shift->SUPER::new(@_) in father::new looks in father's ancestors for a new and calls grandfather::new.
  3. $class->SUPER::new(@_) in grandfather::new looks in grandfather's ancestors for a new and calls Class::Accessor::Fast::new.

By the way, the behaviour of shift->SUPER::new(@_) is undefined. Don't modify and use a variable (@_) in the same statement.

In reply to Re: Why doesn't SUPER cause dead loop here? by ikegami
in thread Why doesn't SUPER cause dead loop here? by PerlOnTheWay

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