You say you think it's defined, but the only thing you gave to back that up is that other things aren't defined. Please show where it is defined if it is.

The operand evaluation order is well known* for all operators, but it's only documented for some. It's not for the arrow operator (docs below). Off the top of my head, operand evaluation order is only defined for the following operators:

From perlop:

"->" is an infix dereference operator, just as it is in C and C++. If the right side is either a [...], {...}, or a (...) subscript, then the left side must be either a hard or symbolic reference to an array, a hash, or a subroutine respectively. (Or technically speaking, a location capable of holding a hard reference, if it's an array or hash reference being used for assignment.) See perlreftut and perlref.

Otherwise, the right side is a method name or a simple scalar variable containing either the method name or a subroutine reference, and the left side must be either an object (a blessed reference) or a class name (that is, a package name). See perlobj.

As you can see, there's no mention of operand evaluation order.

* — Meaning all existing versions of Perl use the same order.

** — Short-circuiting nature and thus operand evaluation order is not actually documented, but it is strongly expected.

*** — Operand evaluation order is inferred from documented ability to do my $x = $x; and local $x = $x;.

In reply to Re^3: Why doesn't SUPER cause dead loop here? by ikegami
in thread Why doesn't SUPER cause dead loop here? by PerlOnTheWay

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