I don't know why you want to do this, but if you store the Regexp as a string, you allready have the pattern: 

my $regex = 'foo\\d+|bar\S+?';
...
m/($regex)/;

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Now, matched part of the $_ is in $1 and the pattern corresponding to this, is in $regex.

-- 
Ronald Fischer <ynnor@mm.st>

In reply to Re: Regex: return the pattern instead of the actual match by rovf
in thread Regex: return the pattern instead of the actual match by Deus Ex

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