So you want $1 eq $regex? You cannot directly assign to $1, but try this: 
if ($_ =~ m/($regex)/ && $regex =~ /(.*)/s) {
    ... Now $1 will contain $regex ...
}

[download]
I just cannot figure out why you want this.

In reply to Re: Regex: return the pattern instead of the actual match by JavaFan
in thread Regex: return the pattern instead of the actual match by Deus Ex

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