On closer inspection, this doesn't seem to be quite a complete solution. The below section of the approach I think is expected to return the replaced value, in this case 'ID'.

It instead returns a 1 if a replacement is made or an empty string if it is not. It happens to produce the correct sort in this case because of the narrow data set used.

my $string = 'ID13';
say scalar( $string =~ s/\d+// );

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Does anyone else know of a way to return the correct match in place of this line? The below is a very poor solution I expect.

my $string = 'ID13';
say join('', grep( /[A-Za-z]/, split('',$string) ) );

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In reply to Re^3: Sorting array by Kc12349
in thread Sorting array by fdegir

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