By blindly changing "AoA" to "{$AoAref}",
for my $i (0 .. $#AoA){ my $aref = $AoA[$i]; print "array is: $AoA[$i]\n"; $arg1 = $AoA[$i] if $AoA[$i][0] == "160001"; $arg2 = $AoA[$i] if $AoA[$i][0] == "170001"; $arg3 = $AoA[$i] if $AoA[$i][0] == "670002"; }
becomes
for my $i (0 .. $#{$AoAref}){ my $aref = ${$AoAref}[$i]; print "array is: ${$AoAref}[$i]\n"; $arg1 = ${$AoAref}[$i] if ${$AoAref}[$i][0] == "160001"; $arg2 = ${$AoAref}[$i] if ${$AoAref}[$i][0] == "170001"; $arg3 = ${$AoAref}[$i] if ${$AoAref}[$i][0] == "670002"; }
We can clean this up, some, though.
for my $i (0 .. $#$AoAref){ my $aref = $AoAref->[$i]; print "array is: $AoAref->[$i]\n"; $arg1 = $AoAref->[$i] if $AoAref->[$i][0] == "160001"; $arg2 = $AoAref->[$i] if $AoAref->[$i][0] == "170001"; $arg3 = $AoAref->[$i] if $AoAref->[$i][0] == "670002"; }
or if you actually use the $aref you created,
for my $i (0 .. $#$AoAref){ my $aref = $AoAref->[$i]; print "array is: $aref\n"; $arg1 = $aref if $aref->[0] == "160001"; $arg2 = $aref if $aref->[0] == "170001"; $arg3 = $aref if $aref->[0] == "670002"; }
And to get rid of useless $i:
for my $aref (@$AoAref) { $arg1 = $aref if $aref->[0] == "160001"; $arg2 = $aref if $aref->[0] == "170001"; $arg3 = $aref if $aref->[0] == "670002"; }

In reply to Re: Looping on Array of Arrays (by References) by ikegami
in thread Looping on Array of Arrays (by References) by jjap

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