I just could not figure out how /m works with ^ in the regular expression matching. I tested the following codes:
"AAC\nGTT"=~/^.*$/m;
print $&;
which gives AAC.
However since /m makes ^ and the $ match around embeded newlines, for me the last pattern match should be GTT.
The modified code give the same result:
"AAC\nGTT\n"=~/^.*$/m;
print $&;
So, it looks to me the /m did not modify the ^ default behavior. Please help me with this entry-level question. Thanks.

In reply to /m pattern matching modifier by tandx

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