You can achieve your goal thus:

sub undefRef{ 
    my $ref = shift; 
    undef @{ $ref };
}

[download]

But why you would do undefRef( \@a ); rather than undef @a; I cannot see.

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In reply to Re: passing reference to subroutine by BrowserUk
in thread passing reference to subroutine by asthaonard

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