When I removed the parentheses from my subroutine (sorry for using function before) definition, the error ceased to appear.

Updated: Given what Zaxo said below, why does the error disappear when I remove the perentheses from the subroutine definition? Since I am in fact no longer "prototyping" the subroutine, does it just relax and assume that I know what I'm doing when I call it before it has been defined? It seems that perl -w and use strict still ought to catch the fact that I'm calling the it before it's been defined.

In reply to Re: Re: Function Prototypes by mvaline
in thread Function Prototypes by mvaline

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