my $foo = "4D";
my $bar = "\x4D";

print $bar . "\n";

[download]

Doesn't produce

Illegal hexadecimal digit '$' ignored at roman.pl line 10.
4D.

[download]

Why don't you please edit your post and include the actual code that is giving you that error message? I suspect I know what it looks like, but it's your job to actually show code that exhibits the problem you're describing.

At any rate, hex will, given the string contained in $foo as a parameter, return the base ten integer value 77.


Dave

In reply to Re: Escaping a variable by davido
in thread Escaping a variable by Draxter

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