Well, first off, by putting parens around "vodka=(\d{2})", you've created another capture, but the approach that might have been "correct" also doesn't work:
my $re = qr/beer=(\d{2}).*(?:vodka=(\d{2}))?.*chips=(\d{3})/;
That "matches" both strings, but doesn't capture the number that follows "vodka" in the first string. Sorry, but I can't explain why.

So I'd be inclined to take a different approach:

#!/usr/bin/perl use strict; use warnings; my @strs = ( "beer=10&otherstuff&vodka=20&otherstuff&chips=100", "beer=10&otherstuff&juice=20&otherstuff&chips=100" ); my @targets = qw/beer vodka chips/; for ( @strs ) { my @matched; for my $target ( @targets ) { push @matched, $1 if ( /$target=(\d+)/ ); } if ( @matched ) { print "matched: @matched\n"; } }
UPDATE: Here's a variant on that approach, which I think is closer to what your own snippet would actually do if it worked (in case that's really what you want):
my @targets = qw/beer=(\d{2}) (vodka=(\d{2})) chips=(\d{3})/; for ( @strs ) { my @matched; for my $target ( @targets ) { push @matched, ( /$target/ ); } if ( @matched ) { print "matched: @matched\n"; } }

In reply to Re^3: Likely trivial regex question by graff
in thread Likely trivial regex question by moodywoody

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