Small correction, 1e9! / (1e9-4)! would not be 1/(1*2*3*4) but 1/(999999997*999999998*999999999*1000000000)

And you are probably thinking about the binomial coefficient, which is n! / ( k! * (n-k)! )

In reply to Re^3: Operations with Extremely Large Numbers by jethro
in thread Operations with Extremely Large Numbers by jjw017

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