Howdy!

Given subsequent clarifications, I think this may be a very effective approach. If you look at the first n items in the array, you will get the entire group each time. Once you have handled a set, shift the first element off and any subsequent empty elements. Lather, rinse, repeat.

yours,
Michael

In reply to Re^2: How to code this? by herveus
in thread How to code this? by BrowserUk

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