I am having trouble understanding even the basics of this C code.
TaskCode() returns a pointer to anything and accepts a pointer to anything.

There is nothing returned from this C subroutine,
void *TaskCode(void *argument).

tid = *((int *) argument);
means: argument is "cast" as a pointer to integer.
Then that result is de-referenced to get the "tid". A **int.

The OP's code is a memory leak because there is no pointer or other way to use the memory allocated by
"s = (char*) malloc(100);". 

void *TaskCode(void *argument) 
{
   int tid;
   char * s;

   tid = *((int *) argument);
   // tid = **argument;

   printf("thread %d: calling malloc\n", tid);
   s = (char*) malloc(100);
   printf("thread %d:  malloc called\n", tid);

   return NULL;
}

[download]
"s" is a memory pointer returned by malloc(). Now a malloc() call should have a conditional statement to see that it actually worked. But the big thing here is that the subroutine TaskCode() returns bullshit. I don't see how "s", the pointer to a new memory allocation of 100 bytes can ever be used outside of TaskCode()

In reply to Re: [Win32] pthreads and memory allocation by Marshall
in thread [Win32] pthreads and memory allocation by syphilis

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