This is a combinatorial problem I think in essence, but I'm not interested in the number of combinations rather how to get them. If I'm working with a number of arrays (stored in an AoA or whatever data structure you want, but I think AoA is best) I need to return the sum of the elements of each combination of the arrays. I can do NC2 but I can't seem to figure out how to get up to NC3 let alone NCN with an algorithm (which is what I'm hoping someone can help me with)
(All arrays in the AoA are the same size, hence my use of @$AoA[0] for size in the 3rd for loop)
Here's NC2:
#!/usr/bin/perl
use strict;
use warnings;
my @newAoA;
my @AoA = ( [1,1,1],[0,0,0],[1,0,1],[0,0,1] );
my $arrRef = $AoA[0];
my $c = 0;
for (my $i = 0; $i < scalar @AoA ; $i++){
for (my $j =$i+1; $j< scalar @AoA ; $j++){
for (my $k=0; $k< scalar @$arrRef; $k++){ ### scalar @$AoA[0]
+doesn't work, maybe im losing my mind but thats the same as @$arrRef
push @{$newAoA[$c]}, ($AoA[$i][$k] + $AoA[$j][$k]);
}
$c++;
}
}
foreach my $array (@newAoA){
print @$array,"\n";
}
foreach my $array (@newAoA){
print @$array,"\n";
}
prints:
111
212
112
101
001
102
edit: sorry, I was a bit rusty too much java lately *sigh*. This code works
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