In the first case, you are assigning to an array @a. The first element of the array will be the reference to the anonymous array containing 4 values.
In the second case, you assign the reference directly to a scalar variable $a.
Or, as SuicideJunkie put it in the CB: in the first case, $a[0][2] == 3 and in the second case, $a->[2] == 3

In reply to Re: difference between @, $ by choroba
in thread difference between @, $ by soubalaji

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