I like choroba's answer, it's exactly the way it works. On a theoretical note:
* List/Array assignment: @list=('el1','el2','el3');
(Note, the parenthesis indicate that a regular array initialisation is being carried out.)
* Array Reference Assignment: $aref=['el1','el2','el3']
(Note, the scalar variable $aref is being assigned a reference to a list, enclosed in square brackets).

Enjoy!

In reply to Re: difference between @, $ by sumeetgrover
in thread difference between @, $ by soubalaji

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