In your line 7, did you intend for $i < @in; to be $i < $#in; ? ... or, maybe $i < ( $#in + 1 );? @in is the entire array; not a count of elements

How does someone who's been around here as long as you, miss the fact that an array reference @a in a scalar context (as provided by a comparison operator), renders the number of elements in the array. Ie. exactly the same number as $#a + 1?

With the rise and rise of 'Social' network sites: 'Computers are making people easier to use everyday'
Examine what is said, not who speaks -- Silence betokens consent -- Love the truth but pardon error.
"Science is about questioning the status quo. Questioning authority".
In the absence of evidence, opinion is indistinguishable from prejudice.

The start of some sanity?

In reply to Re^2: Can you help profile this? by BrowserUk
in thread Can you help profile this? by Fighter2

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