Yes, that works, but not strictly because it's in a loop. It works because you're creating a new hash inside the scope of the loop, and pushing a reference to that new hash to your array. That hash goes out of scope at the end of the loop, so the next time through the loop, you're creating a brand new hash. If you moved my %recordset; outside the loop, you'd have the same problem as before, because it would have scope outside the loop and not be created anew each time.

You could do the same thing outside a loop, as other people have shown, but it would be more awkward.</c>

Aaron B.
My Woefully Neglected Blog, where I occasionally mention Perl.

In reply to Re^4: Newbie hash/sorting question by aaron_baugher
in thread Newbie hash/sorting question by msensay

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