:D Because m// and s/// are different operators that behave differently :D

s/// always returns the number of matches, unless you use /r, in which case it returns a string copy see perlop#s/PATTERN/REPLACEMENT/msixpodualgcer 

my @c;
s/(...)/ push @c, $1; q[X]; /ge

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In reply to Re: s///g and capturing all matches by Anonymous Monk
in thread s///g and capturing all matches by Random_Walk

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