And that's the part where I disagree. If $a->{b} doesn't exist, we know that $a->{b}{c} cannot exist,
But he isn't checking if $a->{b} exists, so it's possible that $a->{b}{c} can exist. Perl is being asked if $a->{b}{c} exists, and it's being done a few steps after autovivifying $a->{b}.
In reply to Re^5: When DOESN'T "Use of uninitialized value" show up?
by ikegami
in thread When DOESN'T "Use of uninitialized value" show up?
by Tim McDaniel
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